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Statistics problem?


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  #1  
Old 06-15-2008, 01:38 AM
news news is offline
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Default Statistics problem?

A freight train is going to carry four tankers, six coal cars, and ten lumber cars. How many different arrangements of cars are possible? Please show the solution. Thanks in advance.


The answer is already given. The answer is 240. I just would like to know to solve it.
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  #2  
Old 06-15-2008, 01:38 AM
Bean Bean is offline
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Default Statistics problem?

6 times 4 times 10 = 240
With arrangements, think of them as trees with branches.
The first tanker can have 6 DIFFERENT coal cars and 10 DIFFERENT lumber cars. 60 different possibilities with 4 tankers. 240
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Old 06-15-2008, 01:38 AM
Ideal Ideal is offline
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Default Statistics problem?

4 tankers
6 coal cars
10 lumbar cars

if it is just the the tankers and the coal cars then it would be 4*6= 24 different arrangememts. If it was the coal cars and the lumbar cars it would be 6*10=60 different arrangements. But since its all three then the you just multiple the number of cars of each type. So 4*6*10=240 different arrangemets
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Old 06-15-2008, 01:38 AM
gonorth gonorth is offline
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Default Statistics problem?

# possibilities = a * b * c

with a,b and c being the number of different types.

always try to imagine the problem with smaller numbers
for example : 1 red item - 2 blue items - 3 green items

red - blue - green
red - blue - blue - green
red - blue - green - green
red - blue - blue - green - green
red - blue - green - green -green
red - blue - blue - green - green - green

These are all the possibilities 1 * 2 * 3 = 6


2nd example : how many numbers you can make with 3 digits : 10 * 10 * 10 = 1000 (you have 10 different numbers for each digit)

from : 000 to 999
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